Troubleshooting

fader scales not equal in lemur and cubase

Started by ahcvankampen on .

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8 posts

Not sure what the question is.

The fader of Lemur has an internal range of 0 to 1 which is then translated into midi messages of a range from 0 to 127. After that, the CC midi message with value 0 (Lemur internal 0) is naturally connected to the controlled fader value "minimum" (whatever that is) and then CC midi message with value 127 (Lemur internal value 1) is naturally connected to the controlled fader value "maximum" (whatever that is).

What exactly is not happening from the above?
Hi,
I have the same problem.
I created a fader. If I set the fader value to 0.81 I get 0db in total mix.
Is it possible to set a formula in the value field, so that lemur shows the same value as total mix?

Thank you so much
it is sometimes not easy to replicate a fader. What I often do is set a value in the DAW (0dB, +6dB, -3dB, -12dB, etc.) and put a small line and value for each at the fader's position in Lemur (the DAW must be able to send data). Then the Lemur fader may not look the same as in the DAW, but the values next to the fader remain correct.
Sample the dB readout in your software for many "positions" of the fader. For a midi accurate solution, you need to sample 128 values (midi positions of fader 0-127)

Create a vector, lets call it "dbvals" and fill it with the sampled values.

use dbvals[fader.x*amountofsamples] to display as dB readout

Example:
https://forum.liine.net/viewtopic.php?f=34&t=1552&start=10#p10643
Softcore wrote:Sample the dB readout in your software for many "positions" of the fader. For a midi accurate solution, you need to sample 128 values (midi positions of fader 0-127)
It seems, there is regimentation in the field lenght for a vector....
Hi everyone,

it's an old post but I turn it on again.
I looked for a solution to fix the scales of the Lemur's monitors on those of Cubase but it doesn't works. I also try the Softcore's example without success.
The best solution I have found is based on the following equation:
20*(log(x*127/108))*6/3.241
but the result isn't good because the range seems to go from -200dB to +6dB. And Cubase's faders are in a range going from -121dB (-inf) to +6dB.
So if someone (with much more math skill than me) has an idea on how to convert on the right range I would be really thankful.

For information, here are the correspondences of Lemur monitor data from 0 to 1 for the Cubase's fader (dB).
0.00000 = -121 dB (-inf)
0.00787 = -80 dB
0.02362 = -60 dB
0.14175 = -30 dB
0.25197 = -20 dB
0.33858 = -15 dB
0.44882 = -10 dB
0.59055 = -5 dB
0.78740 = 0.0 dB
0.81102 = +1 dB
0.84252 = +2 dB
0.90551 = +4 dB
0.99213 = +6 dB
1.00000 = +6.02 dB