scripting questions: MIDI_ARGS

Hi guys, I"m new to Lemur and am really loving the possibilities. The one thing I ran into is that there is no Pro Tools support, so I'm taking a crack at doing some basic PT control. I have fader moves and mutes working from Lemur to PT, and now I'm working on receiving data from PT. I can't find any documentation on how MIDI_ARGS work though.

All my data from PT comes in the form of two controller messages per command. So for example, mute light indicator is:

0xB0,0x0C,0x00
0xB0,0x2C,0x42

I've set up a script with execution set to ( On MIDI : B0 : Midi 1 : 0-127 : 1-1 )

But I don't understand the data structure so I'm not sure where to go next. From my forum searches it sounds like MIDI_ARGS is an array but I can't seem to get it working. I've tried the following:

decl mutebyte1 = MIDI_ARGS[12];
decl mutebyte2 = MIDI_ARGS[44];
if (mutebyte1 = 0x00 && mutebyte2 == 0x42) x = 1;
if (mutebyte1 = 0x00 && mutebyte2 == 0x02) x = 0;

and also

decl mutebyte1 = MIDI_ARGS[0x0C];
decl mutebyte2 = MIDI_ARGS[0x2C];
if (mutebyte1 = 0x00 && mutebyte2 == 0x42) x = 1;
if (mutebyte1 = 0x00 && mutebyte2 == 0x02) x = 0;

But no luck. I also tried sending the MIDI_ARGS to the monitor object so I could try to see what the data stream was but I couldn't get that happening either. Any help would be appreciated!

One more question...how can I differentiate between a local expression change of x and a remote change of x so I don't get a feedback loop?

Never mind I seem to have figured it out

I found that if you only look at one controller at a time in "On Expression", MIDI_ARGS[0] is controller # and MIDI_ARGS[1] is the data byte.

And I got the feedback loop killed. Here's my code in case someone else is searching for a solution later:

decl remote_status;
if (byte1 == 0x00 && byte2 == 0x42) remote_status = 1;
else if (byte1 == 0x00 && byte2 == 0x02) remote_status = 0;
else remote_status == -1;

if (x != remote_status)
{
ctlout(1,0x0F,0x00,1);
ctlout(1,0x2F,0x42,1);
}